How many grams of aluminum sulfide can form from the reaction 9.00 g of aluminum with 8.00 g of sulfur

Answer : The mass of aluminum sulfide form from the reaction can be 12.5 grams.

Solution : Given,

Mass of Al = 9.00 g

Mass of = 8.00 g

Molar mass of Al = 27 g/mole

Molar mass of = 256 g/mole

Molar mass of = 150.2 g/mole

First we have to calculate the moles of Al and .

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

From the balanced reaction we conclude that

As, 3 mole of react with 16 mole of

So, 0.0312 moles of react with moles of

From this we conclude that, is an excess reagent because the given moles are greater than the required moles and is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of

From the reaction, we conclude that

As, 3 mole of react to give 8 mole of

So, 0.0312 moles of react to give moles of

Now we have to calculate the mass of

Therefore, the mass of aluminum sulfide form from the reaction can be 12.5 grams.

the mass of the cathode increases because ions from the solution get reduced to atoms and become part of the cathode.

explanation:

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