Chemistry, 03.08.2019 15:50 katietinary1657

What volume of gold would be equal in mass to a piece of copper with a volume of 141 ml? the density of gold is 19.3 g/ml; the density of copper is 8.96 g/ml?

Answers: 1

Show answers

Answers

We are tasked to solve for the volume of Gold given that the mass of Gold is equivalent to that of a copper.

Details:

Density of Copper= 8.96 g/ml
Volume of Copper=141 ml
mass of Gold = mass of Copper
Density of Gold=19.3 g/ml

In order to solve for the mass of copper, we need to use the density formula
Density= mass/volume

Since we are to solve for the mass of copper
mass of copper= Density of Copper * Volume of Copper
mass of copper= 8.96 g/ml* 141 ml= 1263.36 g
Thus,
mass of gold=mass of copper=1263.36 g
Hence,
Using still the density formula to solve for the volume of gold,
Volume of gold=mass of gold/ Density of gold
Volume of gold=1263.36 g/ 19.3 g/ml = 65.46 mL

Therefore, the volume of the gold must be 65.46 mL in order to have the same mass of a copper

Answer from: chloejason8375

Taking into account the definition of density, the volume of gold that would be equal in mass to a piece of copper with a volume of 141 mL is 64.459 mL.

First you must know that density is defined as the property that matter, whether solid, liquid or gas, has to compress into a given space.

In other words, density is a quantity referred to the amount of mass in a given volume, that is, it is the relationship between the weight (mass) of a substance and the volume it occupies.

Then, the expression for the calculation of density is the quotient between the mass of a body and the volume it occupies:

$density=\frac{mass}{volume}$

In this case, for a piece of copper you know that:

Density copper= 8.96 $\frac{g}{mL}$ mass copper= ? Volume copper= 141 mL

Replacing in the definition of density:

$8.96\frac{g}{mL} =\frac{mass copper}{141 mL}$

Solving:

mass copper= 8.96 $\frac{g}{mL}$ × 141 mL

mass copper= 1,263.36 g

To calculate the volume of gold that would be equal in mass to a piece of copper with a volume of 141 mL, you know that:

density gold= 19.3 $\frac{g}{mL}$ mass gold= mass copper= 1,263.36 gvolume gold= ?

Replacing in the definition of density:

$19.3\frac{g}{mL}=\frac{1,263.36 grams}{volume gold}$

Solving:

19.3 $\frac{g}{mL}$ × volume gold= 1263.36 grams

$volume gold=\frac{1,263.36 grams}{19.3\frac{g}{mL}}$

volume gold= 65.459 mL

In summary, the volume of gold that would be equal in mass to a piece of copper with a volume of 141 mL is 64.459 mL.

Learn more about density:

link link

Answer from: Quest

1= c 2= a or d3 = idk sorry 4= c5= c

Answer from: Quest

the answer is a for sure mark brainliest i had got this right on usatestprep

Another question on Chemistry

Chemistry, 22.06.2019 03:10

Agas diffuses 1/7 times faster than hydrogen gas (h2). what is the molar mass of the gas? 100.10 g/mol 98.78 g/mol 86.68 g/mol 79.98 g/mol

Answers: 3

Answer

Chemistry, 22.06.2019 15:00

Many ionic compounds and a few highly polar covalent compounds are because they completely ionize in water to create a solution filled with charged ions that can conduct an electric current.

Answers: 1

Answer

Chemistry, 22.06.2019 20:00

Phosphoric acid is a triprotic acid ( =6.9×10−3 , =6.2×10−8 , and =4.8×10−13 ). to find the ph of a buffer composed of h2po−4(aq) and hpo2−4(aq) , which p value should be used in the henderson–hasselbalch equation? p k a1 = 2.16 p k a2 = 7.21 p k a3 = 12.32 calculate the ph of a buffer solution obtained by dissolving 18.0 18.0 g of kh2po4(s) kh 2 po 4 ( s ) and 33.0 33.0 g of na2hpo4(s) na 2 hpo 4 ( s ) in water and then diluting to 1.00 l.

Answers: 3

Answer

Chemistry, 22.06.2019 21:30

Describe at least two advantages and two disadvantages of using hydropower as a source of energy.

Answers: 2

Answer

You know the right answer?

What volume of gold would be equal in mass to a piece of copper with a volume of 141 ml? the densit...

Questions