How many calories of are required to heat 731 grams of water from 35°c to 83°c? (assume that the specific heat of water is 1.00 cal/g·°c)?

The calories required = 35088

Explanation:

The heat required can be calculated by using specific heat of the water and mass and temperature raised.

The specific heat of water is the amount of heat required to raise the temperature of one gram of water by one degree celsius

Thus

Heat required = mass of water X specific heat X change in temperature

Given:

Specific heat of water = 1 cal /g °C

mass of water = 731 g

change in temperature = 83-35 = 48°C

Putting values

a gas, having a molecular weight of 13 kg/kmol and a kinematic viscosity of 0.25 cm2/s, flows through a pipe 0.25 m internal diameter and 5 km long at the rate of 0.4 m3/s and is delivered at atmospheric pressure.

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