How many grams of carbon dioxide (co2) are found
in a 11.9 l container under 1.5 atm and 20.0oc.

PV=nRT

p = 1,5atm = 1,5*101325 = 151987,5 Pa
V = 11,9l = 0,0119m3
n = ?
R = 8,314 J/mol*K
T = 20°C = 20+273 = 293K

pV=nRT
151987,5*0,0119 = n*8,314*293
1808,6513=n*2436,002  ||:2436,002
0,7425 = n >>> moles of CO2

1 mole of CO2 = 44g

1 mole of CO244g
0,7425 moles of CO2x
x = 32,67g of CO2

Ithe undersigned only for use your own email and delete any and copies and of the itself and to be there is a good timewhat does a decrease in temperature indicate about the molecules in a sample of liquid water? decreased chemical energy of the moleculesdecreased kinetic energy of the moleculesincreased chemical energy of the moleculesincreased kinetic energy of the moleculeshow does a sample of helium at 15 â°c compare to a sample of helium at 215 k? the helium at 15 â°c has a higher average kinetic energy than the sample at 215 k.the helium at 15 â°c has lower nuclear energy than the sample at 215 k.the helium at 15 â°c has slower-moving atoms than the sample at 215 k.the helium at 15 â°c has smaller atoms than the sample at 215 k.