Which conversion factor should you use first to calculate the number of grams of co2 produced by the reaction of 50.6 g of ch4 with o2?

Answer is: 1 mol CH₄/16,0 g CH₄.
Chemical reaction: CH₄ + 2O₂ → CO₂ + 2H₂O.
m(CH₄) = 50,6g.
M(CH₄) = 16g/mol.
n(CH₄) = m(CH₄) ÷ M(CH₄) = 50,6g ÷16g/mol = 3,16mol.
n(CH₄) : n(CO₂) = 1:1.
nCO₂) = 3,16mol.
m(CO₂) = m(CO₂) · m(CO₂) = 3,16mol · 44g/mol = 139,15g.
M - molar mass.
n - amount of substance.

m=9

step-by-step explanation:

7m+8=71 subtract   8 from 71 which is 63 than divide it by 7m   equal 9.

                             

It was ernest rutherford