The volume of hcl gas required to react with excess magnesium metal to produce 6.82 l of hydrogen gas at 2.19 atm and 35.0 â°c is l

3.41LHCl

Explanation:

Hello! Let's solve this!

First we must raise the balanced equation

2HCl + Mg > H2 + MgCl2

From the equation we can see that the ratio of moles is 2: 1

2moles of HCl per 1 mol of H2

We know that the volume of H2 is 6.82L

So we follow the following relationship

6.82LH2 * (1mol H2 / 2molHCl) = 3.41LHCl

answer : one can design an experiment using a liquid and an additive that can be added to the liquid and observe the chemical changes in the reaction species.

one would need a beaker which is filled with a known amount of the liquid in which thermometer is placed to measure the temperature changes; after addition of the additive to the liquid solution one can note down the temperature change and find whether the reaction is endothermic or exothermic in nature. by subtracting the initial temperature value with the final temperature one can find the temperature changes.

various combinations of liquid and additive can be used. liquid in this case can be a known quantity of water and additives can be epsom salt or without epsom salt the experiment can be conducted to notice the changes. water and ice, hydrogen peroxide and dry yeast, vinegar and baking soda,etc.