Asample of o2 gas (2.0 mmol) effused through a pinhole in 5.0 s. it will take s for the same amount of co2 to effuse under the same conditions.

If a sample of O₂ gas (2.0 mmol) effused through a pinhole in 5.0 s, it will take 5.9 s for the same amount of CO₂ to effuse under the same conditions.

A sample of O₂ gas (2.0 mmol) effused through a pinhole in 5.0 s. The rate of effusion of O₂ is:

Knowing their molar masses (M), we can calculate the rate of effusion of CO₂ using Graham's law.

The rate of effusion of CO₂ is 0.34 mmol/s. The time for 2.0 mmol to effuse is:

If a sample of O₂ gas (2.0 mmol) effused through a pinhole in 5.0 s, it will take 5.9 s for the same amount of CO₂ to effuse under the same conditions.

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The time taken for the same amount of CO₂ to effuse under the same condition is 5.9 s

Let t₁ be the time taken for O₂ to effuse

Let M₁ be thr molar mass of O₂

Let t₂ be the time taken for CO₂ to effuse

Let M₂ be the molar mass of CO₂

Time taken for O₂ to effuse (t₁) = 5 s

Molar mass of O₂ (M₁) = 2 × 16 = 32 g/mol

Molar mass of CO₂ (M₂) = 12 + (2×16) = 44 g/mol

Time taken for CO₂ to effuse (t₂) = ?

Cross multiply

Therefore, it will take 5.9 s for the same amount of CO₂ to effuse under the same condition.

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when 25.0 ml of 0.700 mol/l naoh was mixed in a calorimeter with 25.0 ml of 0.700 mol/l hcl, both initially at 20.0 °c, the temperature increased to 22.1 °c. the heat capacity of the calorimeter is 279 j/°c.

the equation for the reaction is:

naoh + hcl → nacl + h₂o

moles of hcl = 0.0250 l hcl ×

0.700

mol hcl

1 l hcl = 0.0175 mol hcl

volume of solution = (25.0 + 25.0) ml = 50.0 ml

mass of solution = 50.0 ml soln ×

1.00

ml soln

= 50.0 g soln

δt=t2-t1

= (22.1 – 20.0) °c = 2.1 °c

the heats involved are

heat from neutralization + heat to warm solution + heat to warm calorimeter = 0

q1+q2+q3=0

nδh+mcδt+cδt=0

0.0175 mol ×

δh

+ 50.0 g × 4.184 j·g⁻¹°c⁻¹ × 2.1 °c + 279 j°c⁻¹ × 2.1 °c = 0

0.0175 mol ×

δh

+ 439.32 j + 585.9 j = 0

0.0175 mol ×

δh

= -1025.22 j

δh=1025.22j0.0175 mol= -58 600 j/mol = -58.6 kj/mol

answer: -

reaction:

na + cl ⇌ nacl

balanced chemical equation:

na + 2cl ⇌ nacl2

sodium + clorine goes to form sodium chloride (table salt).

the product is nacl2.

and the reactants are na and cl.

(note: if you don’t know what ⇌ means, read below: -

⇌(double head arrow) means reversible reaction).