Asample of an unknown substance has a mass of 0.158 kg. if 2,510.0 j of heat is required to heat the substance from 32.0°c to 61.0°c, what is the specific heat of the substance?

Given:

Mass of the unknown substance, m = 0.158 kg = 158 g

Heat absorbed Q = 2510.0 J

Initial temperature T1 = 32 C

Final temperature T2 = 61 C

To determine:

The specific heat of the substance

Explanation:

The heat absorbed to raise the temperature from T1 to T2 is-

Q = mcΔT

where c = specific heat

c = Q/mΔT = Q/m(T2-T1)

c = 2510 J/158 g * (61-32) C = 0.548 J/gC

Ans: Specific of the substance is 0.548 J/gC

  the   balanced   equation   for   reaction of   ca metal   with   o2 to   produce   cao   is as below

2 ca+ o2→ 2 cao2

  explanation

the reaction is   balanced     since the   number of atoms   in reactant side is   equal to   number of atoms   in   product side.   for   example   they   are 2   atom of   ca in   reactant   side   and   2   atoms of ca   in   the product side.

  the   process   is a   meet the   requirement   of   redox   reaction because :     calcium   is   oxidized   from   oxidation state 0   to 2+   while   oxygen   is reduced from   oxidation   state   0   to 2-