The table below shows some physical properties of two unknown samples. physical properties sample mass solubility (in water) c 200 g 36 g/ml d 500 g 180 g/ml what would best support whether the two samples are of the same substance or not?   the two substances are the same because the property that depends on the amount of the sample is different.  the two substances are the same because the property that is independent of the amount of the sample is different.  the two substances are not the same because the property that is independent of the amount of the sample is different.  the two substances are not the same because the property that depends on the amount of the sample is different.

Since the gas in your graduated cylinder is a mixture of butane and water vapor, you must determine the partial pressure of the butane, pbutane, alone. to do this, consult a reference and record the partial pressure of the water vapor, pwater, at the temperature you recorded. use the following formula to compute the partial pressure of the butane. pbutane = atmosphere - pwater use the following combined gas law formula and compute the volume that the butane sample will occupy at stp. (hint: convert both temperatures to kelvin.) pbutane x voriginal = pstandard x vfinal troom tstandard use the following ratio and proportion formula to determine the mass of butane needed to occupy a volume of 22.4 l at stp. grams of butane you used “x” grams of butane ml of butane corrected to stp = 22,400 ml compute the theoretical molar mass of butane based on its formula and the atomic masses on the periodic table. compare your experimental results from #3 to the theoretical value of #4, computing a percent error of your findings using this formula: % error = measured value - accepted value x 100 accepted value use the following ratio and proportion formula to determine the mass of butane needed to occupy a volume of 22.4 l at stp. need asap