How many grams of n are in 89.0 g of nh4no3

Step 1;calculate  the  molar  mass  of   NH4N03 
molar  mass  of different  element
N=14
H=1
O=16
therefore  molar  mass  of  NH4NO3   is 14+4+14+48= 80g/mol
step 2:find the  molar mass of N  present  in  NH4NO3
   That  is  14+14 =28g/mol
the mass  is  therefore
{(28g/mol/80g/mol) x 89g} =31.15g

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