What is the pressure in a 3.41 l container that has 0.741 moles of oxygen gas at 26.0 °c? question 13 options: ?

To answer this question, we will use the general gas law which has the following formula:
PV = nRT where:
P is the pressure of the gas that we need to calculate
V is the volume of gas = 3.41 liter = 0.00341 m^3
n is the number of moles = 0.741 moles
R is the gas constant =  8.314 J/(K·mol)
T is the temperature = 26 degree Celsius = 299 degree kelvin

Substitute with the givens in the above equation to get the pressure as follows:
P*0.00341 = 0.741*8.314*299
P = 540188.1308 Pascal

It conforms what ever surface its in.