How many molecules of co2 are equivalent to 112 g co2? (c=12.01 g/mol, o=16.00 g/mol )

1.532*10^24

Explanation:

Since (C = 12.01 g/mol, O = 16.00 g/mol)

C + O2 → 12.01 + 2(16) = 44.01

(112)(1)(6.02*10^23)/(44.01)

1.532 * 10^24 <- (The answer is with 4 sig figs because of the equation above)

in the given question, the partial pressure is calculated by using the ideal gas equation, that is, pv = nrt

here, p is pressure, v is volume = 25 l, n is number of moles = 0.0104 moles, r is gas constant = -0.0821 l.atm / mol.k

t is temperature = 273 k

p = nrt / v

p = (0.0104 mol × 0.0821 l.atm / mol.k × 273 k) / 25 l

= 0.0093 atm

it should have an internal chamber and two thermometers sticking out of the top. the internal chamber will also be closed off from the outside.