Calculate the rms speed of an oxygen gas molecule, o2, at 29.0 ∘c . express your answer numerically in meters per second.

The rms speed of an oxygen gas molecule : 485.17 m/s

Kinetic Molecular Theory (KMT) states that a gas consists of molecules that move at a constant and random speed. The collisions between molecules are perfectly elastic so that no energy is wasted.

The molecules move in straight lines until they collide

Energy because this motion is expressed as Kinetic energy (KE) which can be formulated as:

The average kinetic energy value is only affected by temperature changes. The higher the temperature, the average kinetic energy of the molecule increases

This molecule is very small when compared to the distance between molecules, so the volume of gas contains mostly empty space

Gas particles move randomly (both speed and direction , as vector)

Average velocities of gases can be expressed as root-mean-square averages. (V rms)

R = gas constant, T = temperature, Mm = molar mass of the gas particles

From the question

R= 8.314 J/mol K

T = 29 + 273 = 302 K

Mm = molar mass O₂ = 2.16 = 32 g/mol = 32.10-3 kg/mol

inertia affect during a collision

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Henry's Law

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ideal gas

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Keywords: Kinetic Molecular Theory, Collisions, The average kinetic energy , the rms speed, gas molecule

right

explanation:

i think it is d. e because the next one is igneous.