Find the mass in 2.6 mol of lithium bromide. (hint:   you need to write the formula)

The mass of 2.6 mol of Lithium bromide is 225.797 g.

The Lithium bromide has the molecular formula: LiBr.

The molecular mass of the LiBr will be the sum of the molar mass of Li and Br.

The molecular mass of LiBr = molar mass of Li + molar mass of Br.

The molar mass of Li = 6.941 u

The molar mass of Br = 79.904 u

The molecular mass of LiBr = 6.941 u + 79.904 u

The molecular mass of LiBr = 86.845 g/mol.

Moles =

weight = moles molecular weight

weight of LiBr = 2.6 86.845 g

Weight of 2.6 moles LiBr = 225.797 g.

The mass of 2.6 mol of Lithium bromide is 225.797 g.

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