Calculate the mass % of na in sodium dihydrogen phosphate heptahydrate.

The formula for sodium dihydorgen phosphate heptahydrate is: NaH2PO4.7H2O To determine the mass % of sodium you first need to find the total mass: 1 Na = 1 x 22.990 = 22.990 16 H = 16 x 1.0079 = 16.1264 1 P = 1 x 30.97 = 30.97 11 0 = 11 x 15.9994 = 175.9934 Total = 246.084 g For the mass % of Sodium: (22.99 g Na/246.084 g total)x 100% = 9.34%

Answerthis solution will not form a precipitateexplanationsolubility equilbrium:         pbf₂(s)  ⇄ pb²⁺(aq) + 2 f⁻(aq)the solubility product expression is    (we exclude solids from the equilibrium expression).now suppose we have the trial ion product q, which we can define as    then, we can interpret  q as the product of the concentration of the ions that we have and ksp as the product of the ion concentrations that are needed to form a saturated solution.if q > ksp, then that implies that there will be a surplus of ions that exceed the amount that is required to form a saturated solution. a precipitate will then form (the precipitate continually  forms until the surplus ions are removed and q is decreased to ksp's value).if q = ksp, the saturated solution that forms is barely saturated and the precipitate will be minimal.if q < ksp, then the ion concentration will not be enough to form a saturated solution (so no precipitate).using our information, we calculate the trial ion product:     since q = 2.7  × 10⁻⁸ < ksp =  4  ×  10⁻⁸, a precipitate will not form.

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