Calculate the volume of 0.0500 m edta needed to titrate ca caco3

EDTA is a complex used to determine water hardness. The reaction between EDTA and CaCO₃ is in 1:1 ratio. To solve this problem, we must know the moles of CaCO₃ present (otherwise we can't solve the problem). Suppose you have 0.5 moles of CaCO₃. Since the ratio is 1:1, it would also need 0.5 moles EDTA. Then,

Volume = Moles/Molarity = 0.5 moles/0.05 M = 10 L of EDTA

the catch is that the top numbers are atomic masses the bottom numbers are the numbers of protons and electrons in an uncharged atom. they are the number of that atoms as you would find them on the periodic table. further, the numbers on the left are used to determine the missing numbers on the right

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer