Part a how many grams of water, h2o, can be formed from the reaction of 6.8 g of 2-propanol, c3h8o? c3h8o⟶c3h6+h2o

In the equation, for every 1 molecule of 2-propanol there will be 1 molecule of water formed. If the molecular mass of 2-propanolol is 60g/mol, the number of molecule of 2-propanolol would be: 6.8g/ (60g/mol)= 0.1133 mol

The number of water molecule formed by the 2-propanolol would be: 1*0.1133 mol= 0.1133 mol

If the molecular mass of water is 18g/mol, the weight of the water would be:0.1133 mol* 18g/mol= 2.04 grams

10.063g / 10.00 ml = 1.0063 g/ml which rounds off to 4 sig figs as: 1.006 g/ml

Icant see the pictures