What is the percent yield of hbr if 85.00 g of hbr was formed from 30. g of h2?

Ok, lets see the definitions of percent yield, actual yield and theoretical yield.

Percent yield is the ratio of actual yield to theoretical yield.

Actual yield- amount of product produced in the EXPERIMENT.

Theoretical yield- max amount of product produced through CALCULATIONS

% yield= actual yield (from experiment)/theoretical yield (from calculation) *100

1st Step: Write the reaction 

H2 + Br2 --> 2 HBr

2nd Step: Get the mass ratio of H2 and HBr to find theoretical yield

1 mole H2 gives 2 moles HBr ( molar mass of H2= 2 g/mol, HBr= 81 g/mol)

2 g H2 gives 2*81= 162 g HBr

30 g H2 gives 162*30/2 = 2430 g HBr ( The equation is 2 g H2/ 30 gH2= 162 g HBr/ x g HBr)

So theoretically 2430 g HBr are produced by calculation ( THEORETICAL YIELD)

By experiment 85 g HBr are produced as it is given at the question ( ACTUAL YIELD)

% yield= actual yield / theoretical yield *100 = 85/2430 *100= 3.5 %

The percent yield is 3.5 %.

dynamic equilibrium is the answer.

conduction is the transfer of thermal energy (heat in transfer) due to collisions between the molecules in the object. collisions between adjacent atoms and molecules transfer kinetic energy from the warmer to the cooler object. the objects must be in physical contact.