Apatient receives all her nutrition from fluids given through the vena cava. every 12hrs, 950ml of a solution that is 9%(m/v) amino acid(protein) and 18%(m/v) glucose is given along with 300ml of a 10%(m/v) lipid solution. how many grams of amino acids, glucose and lipid does the patient receive in a day?

Amino acids = 171 grams/day Glucose = 342 grams/day Lipid = 60 grams/day The first thing to determine is how the concentration is being expressed. Are we using mass percent (m/m), volume percent (v/v), mass/volume percent (m/v) , or molarity (M)? In this problem we're using mass/volume. The formula is: %(m/v) = 100 * (grams solute)/(mL of solution) Let's abbreviate the equation to P = 100g/v where P = % (m/v) g = grams of solute v = volume of solution in mL. Solving for g, we get: P = 100g/v Pv = 100g Pv/100 = g Now let's calculate the answers to the questions: Amino acids = 950 mL of 9% solution: 9*950/100 = 8550/100 = 85.5g per feeding. Glucose = 950 mL of 18% solution: 18*950/100 = 17100/100 = 171g per feeding. Lipid = 300 mL of 10% solution 10*300/100 = 3000/100 = 30g per feeding. Since the patient is being feed twice a day, double all the per feeding values. Sl Amino acids = 85.5g * 2 = 171 grams/day Glucose = 171g * 2 = 342 grams/day Lipid = 30g * 2 = 60 grams/day

Noble gases is far right