Asolution of water (kb=0.512 ∘c/m) and glucose boils at 103.56 ∘c. what is the molal concentration of glucose in this solution? assume that the boiling point of pure water is 100.00 ∘c. express your answer to three significant figures and include the appropriate u

Answer is: molal concentration of glucose in this solution is 6.953 mol/kg.

Kb(H₂O) = 0.512 °C/m.

T(glucose) = 103.56 °C.

T(H₂O) = 100°C.

ΔT = 103.56°C - 100°C.

ΔT = 3.56°C.

ΔT = m(glucose) · Kb(H₂O).

m(glucose) = ΔT ÷ Kb(H₂O).

m(glusose) = 3.56°C ÷ 0.512 °C/m.

m(glucose) = 6.953 mol/kg.

m - molal concentration.

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