If the actual yield of the reaction was 75% instead of 100%, how many molecules of o2 would be present after the reaction is over? the# of no2 molecules is 8 if it goes through completion and no is the limiting reactant.

The reaction for the production of NO₂ is as follows:

2 NO + O₂ → 2 NO₂

Then, we use stoichiometry to solve the problem. The solution is as follows:

8 molecules NO₂ (1 molecule O₂/2 molecules NO₂)(0.75) = 3

Therefore, it will need 3 molecules of oxygen for a 75% yield.

Ur e n d is not real