Which substance is the reducing agent in this reaction? 2cr(oh)3+3ocl−+4oh−→2cro4−2+3cl−+5h 2o express your answer as a chemical formula?

The substance that is a reducing agent is Cr(OH)3.

The term "reducing agent" implies a specie whose oxidation number increases from left to right in the reaction equation. So an the reducing agent must have a lower oxidation number on the left hand side of the reaction equation, but a higher oxidation number on the right hand side of the reaction equation.

We must look out for this as we study the equation;

2Cr(OH)3 + 3OCl^− + 4OH^− ------>  2CrO4^2- + 3Cl^− + 5H2O

It is easy to see from the equation that the oxidation number of chromium increased from +3 on the left hand side of the reaction equation to +6 on the right hand side of the reaction equation.

This means that Cr(OH)3 must be the reducing agent in this reaction.

Learn more; link

Cr(OH)₃  undergo a oxidation reaction (increase in oxidation number) from +3 to +6, so Cr(OH)₃  is the reducing agent

Reduction oxidation reaction or abbreviated Redox is a chemical reaction in which there are changes in oxidation numbers

The general formula for determining oxidation numbers:

On reaction :

2Cr(OH)₃+3OCl⁻+4OH⁻→2CrO₄²⁻+3Cl⁻+5H₂O

Oxidation number at Cr(OH)₃

Cr + 3. H + 3.O = 0

Cr + 3.1. + 3.-2 = 0

Cr + 3 -6 = 0

Cr = +3

Oxidation number at CrO₄²⁻

Cr + 4.O = -2

C + 4.-2 = -2

C = +6

The oxidation number Cr in Cr(OH)₃ is +3 and the oxidation number Cr in CrO₄²⁻ is +6, the change in oxidation number C from +3 to +6 is 3, so the Cr atom experiences an oxidation reaction (increase in oxidation number)

Oxidation number at OCl⁻

O + Cl = -1

-2 + Cl = -1

Cl = +1

Oxidation number at Cl⁻

Cl⁻ = =-1

The oxidation number Cl in OCl⁻ is +1 and the oxidation number Cl in Cl⁻ is -1, the change in Cl oxidation number from +1 to -1 is -2, so that the Cl atom experiences a reduction reaction (decreasing the oxidation number)

While O and H atoms do not experience changes in oxidation numbers (O = -2 and H = +1)

So the reducing agent which is experienced with an oxidation reaction (increase in oxidation number) is Cr(OH)₃

an oxidation-reduction reaction

ainly.com/question/2973661

a reducing agent during a redox reaction

link

loses electrons in a chemical reaction

link

Keywords: reduction, oxidation

answer: you could do some invislibe ink.

explanation: i will tell you how to if u answer my question.

the best answer is d because the strong cohesion is caused by the ability of water molecules to undergo hydrogen bonding.

a is incorrect because when water solidifies, it becomes   ice, which expands and occupies a bigger volume for the same mass of water in its liquid state.

b is incorrect because water has high surface tension. besides bonding to itself it hydrogen bonds to other molecules at the top decreasing possibility for breaking of attractive forces.

c is incorrect because the water molecule has oxygen which is highly electronegative and so pulls the electron pair towards itself creating a dipole moment, making the molecule polar.

e is incorrect because water has strong adhesion, ability to stick to other molecules such as glass because of this molecules having stronger hydrogen bonding than water.