Calculate the net change in enthalpy for the formation of one mole of nitric acid from nitrogen, hydrogen and oxygen from these reactions. round your answer to the nearest kj .

The formation of nitric acid from nitrogen, hydrogen, and oxygen can be written as,

     N₂ + H₂ + 3O₂ --> 2HNO₃

The net enthalpy of formation of nitric acid is calculated by,
   Hrxn = Hproduct - Hreactant

Since all the reactants are in their elemental forms, the simplified equation would be,

    Hrxn = Hproduct 

Substituting,

    Hrxn = (-186.81 kJ/mol)(2 mols)

-372.42 kJ

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