What is the total random kinetic energy of all the molecules in 1 mole of hydrogen?

From gas kinetic theory, one has the result that the total internal energy of a mole of ideal gas particles is equal to the sum of the kinetic energies of each of the particles. For one mole of gas: 

U = (3/2)*R*T 

where R is the universal gas constant (8/314 J/(mol*K) and T is the thermodynamic temperature. 

At 320K, a the total kinetic energy of the molecules in a mole of Kr is: 

U = (3/2)*(8.314 J/mol*K)*(320K) = 2660 J 

One mole of Kr gas has a mass of 83.80 gm, so the center-of-mass velocity of a mole of Kr that has a translational kinetic energy of 2660 J would be: 

2660 J = (1/2)*(8.38*10^-2 kg)*v^2 

6.35*10^4 (m/s)^2 = v^2 

252 m/s = v

All the elements are arranged by melting points on the periodic table. in row they go from metals to gasses. in the row from sodium to argon, sodium is more reactive than the one on its right, magnesium.

Higher temperature = molecules move around faster. and vice versa.