(a) starting with solid sucrose, c12h22o11, describe how you would prepare 250 ml of a 0.250 m sucrose solution. (b) de- scribe how you would

a. We first calculate the moles of sucrose needed

moles sucrose = 0.250 M * 0.25 L

moles sucrose = 0.0625 mol

The molar mass of sucrose 342.3 g/mol, so the mass of sucrose needed is:

mass sucrose = 0.0625 mol * 342.3 g/mol

mass sucrose = 21.4 grams

So simply dissolved about 21.4 grams of sucrose in 250 mL solution.

b. We use the formula:

M1 V1 = M2 V2

1.50 M * V1 = 0.100 M * 0.350 L

V1 = 0.0233 L = 23.3 mL

So simply take 23.3 mL of solution from 1.50 M then dilute it with water until 350 mL to make 0.100 M.

every chemical equation adheres to the law of conservation of mass, which states that matter cannot be created or destroyed. therefore, there must be the same number of atoms of each element on each side of a chemical equation.