Complete the hybridization and bonding scheme for xef4.

Xe = VIII = 8 valence electrons
F = VII = 4 (7 ve) = 28 valence electrons

total ve = 8 + 28 = 36 ve

36 - 4(2) = 28 ve
(there are 2 electrons in each bond x 4 bonds)

28 - 4(6) = 4 
(We assign the remaining electrons to F atoms)

4 - 2(2) = 0 
(Therefore 4 electrons left => we have 2 lone pairs)

The steric number = No. of σ bonds + #lone pairs

= 4 σ bonds + 2 lone pairs = 6 => d²sp³ (6 hybrid orbitals)

4 bonds + 2 lone pairs => square planar

2b2t

explanation:

2b2t

answer is: nuclear fusion produces elements that are heavier than helium.

nuclei combine to form a heavier nucleus, releasing energy.  

for example, fusion of hydrogen atoms at the sun.  

this fusion nuclear reaction is in the inner core of the sun and hydrogen (atomic number 1) is conveted into helium (atomic number 2).  

the inner core is the central region of the sun and all solar energy is produced in the core by nuclear fusion.