The ostwald process is used commercially to produce nitric acid, which is, in turn, used in many modern chemical processes. in the first step of the ostwald process, ammonia is reacted with oxygen gas to produce nitric oxide and water. what is the maximum mass of h2o that can be produced by combining 54.0 g of each reactant?

The maximum mass of water produced when 54.0 g of each reactant are combined in the first step of the Ostwald process is 45.6 g.

Let's consider the balanced equation for the first step of the Ostwald process.

2 NH₃ + 2 O₂ ⇒ NO + 3 H₂O

Considering the balanced equation, the theoretical mass ratio (TMR) of NH₃ to O₂ is:

Considering the given data, the experimental mass ratio (EMR) of NH₃ to O₂ is:

We need 0.5322 g of ammonia per gram of oxygen and we have 1.00 g of ammonia per gram of oxygen. Thus, ammonia is the excess reactant and oxygen is the limiting reactant.

The theoretical mass ratio of O₂ to H₂O is 64.00:54.06. The mass of water produced from 54.0 g of oxygen is:

The maximum mass of water produced when 54.0 g of each reactant are combined in the first step of the Ostwald process is 45.6 g.

You can learn more about the limiting reactant here:

the correct answer would be b. amelia, because the particals of gas move really fast (charged particals) and gas also has a lot of room (particals move independently) so the only answer that has both of those is amelia's.