If it takes three "breaths" to blow up a balloon to 1.2 l, and each breath supplies the balloon with 0.060 moles of exhaled air, how many moles of air are in a 3.0 l balloon? express your answer to two decimal places and include the appropriate units.

It takes 3 breaths to get to 1.2 l. One breath is then (1.2 l) / 3 breaths = .4l/breath. To get to 3.0 l we need the difference from 1.2 l. 3.0-1.2 = 1.8 l. Divide the difference by liters/breath (.4) to get how many needed breaths. (1.8 l)/(.4 l/breath) = 4.5 breaths to get the balloon to 3.0 l. In total there were 3 breaths+ 4.5 breaths = 7.5breaths to get to 3.0 l. To find the total moles multiply 7.5breaths by .060 moles/breath 7.5 breaths*.060moles/breath = .45moles

0.45 moles of air are in a 3.0 l balloon

Further explanation

Algebraic expressions in mathematics are a combination of coefficients, numbers, variables, constants and arithmetic operations such as addition, subtraction, multiplication, and division.

The main composition of algebraic expressions are:

1. phrases

algebraic forms separated by arithmetic operations

consists of one phrase (monomial) to many phrases (polynomial)

2. variable

is a value that can be changed, can be in the form of letters, for example, x, y, a, b, etc.

3. constants

is a fixed value, can be a number

4. arithmetic operations ⇒ +, -,:, x

it takes three "breaths" to blow up a balloon to 1.2 l

we translate this sentence into Algebraic expressions:

3 breaths = 1.2 L

So for 3.0 l balloon will need:

3: 1.2 x 3 breaths = 7.5 breaths

Because each breath supplies the balloon with 0.060 moles of exhaled water, then for 3.0 L balloon there will be:

7.5 breaths x 0.060 = 0.45 moles

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