1. fill in the chart below (table  below) by writing formulas for the compounds that might form between the ions in the columns and rows. some of these compounds don’t exist but you can still write formulas for them.

The chemical formula of the compound produced from the reaction of the anion (a negatively charged ion) with formula of A⁻ᵃ and a cation (a positively charged ion) with formula B⁺ˣ can be written as,
            BₐAₓ

The answers to the questions above:

Row 2, Column 2: Na⁺ and NO⁻³  : Na₃NO
Row 2, Column 3: Ca²⁺ and NO⁻³ : Ca₃(NO)₂
Row 2, Column 4: Fe³⁺ and NO⁻³ : Fe₃(NO)₃
    This can be furthered reduced to: FeNO
Row 2, Column 5: NH⁴⁺ and NO⁻³ : (NH)₃(NO)₄
Row 2, Column 6: Sn⁴⁺ and NO⁻³ : Sn₃(NO)₄

For the third row anion, S₂⁻
Row 3, Column 2: Na⁺ and S₂⁻ : NaS₂
Row 3, Column 3: Ca²⁺ and S₂⁻ : CaS₄
Row 3, Column 4: Fe³⁺ and Si₂⁻ : FeS₆
Row 3, Column 5: NH⁴⁺ and S₂⁻ : NHS₈
Row 3, Column 6: Sn⁴⁺ and S₂⁻ : SnS₈

For Row 4 anion, PO₃⁻⁴
Row 4, Column 2: Na⁺ and PO₃⁻⁴: Na₄PO₃
Row 4, Column 3: Ca²⁺ and PO₃⁻⁴ : Ca₄(PO₃)₂
Row 4, Column 4: Fe³⁺ and PO₃⁻⁴ : Fe₄(PO₃)₃
Row 4, Column 5: NH⁺⁴ and PO₃⁻⁴ : (NH)₄(PO₃)₄
     This can be further simplified into NHPO₃
Row 4, Column 6: Sn⁴⁺ and PO₃⁻⁴ : Sn₄(PO₃)₄
     This can be further simplified into SnPO₃

For Row 5 anion, CO₂⁻³
Row 5, Column 2: Na⁺ and CO₂⁻³ : Na₃CO₂
Row 5, Column 3: Ca²⁺ and CO₂⁻³ : Ca₃(CO₂)₂
Row 5, Column 4: Fe³⁺ and CO₂⁻³ : Fe₃(CO₂)₃
    this can be further simplified into FeCO₂
Row 5, Column 5: NH⁴⁺ and CO₂⁻³ : (NH)₃(CO₂)₄
Row 5, Column 6: Sn⁴⁺ and CO₂⁻³ : Sn₃(CO₂)₄

Hope you find the answer

H tricky one let me think and get back to u