What will be final temperature if you mix the 50.g of water at 0.0oc to 50.g of water at 100.0oc?

Given:

Mass of water = 50 g

Temperature of cold water Tc= 0 C

Temperature of hot water Th= 100 C

To determine:

Final temperature Tf of water

Explanation:

Heat (Q) absorbed or evolved by a substance is given as-

Q = mc(Tf-Ti)

m = mass

c = specific heat

Tf and Ti are the final and initial temperatures

In this case:

Heat lost by hot water = Heat gained by cold water

-mc(Tf - 100 ) = mc(Tf-0)

-Tf + 100 = Tf

2Tf = 100, i.e. Tf = 50 C

Ans: the final temperature is 50 C

"standard molar enthalpy:

h2o ( liquid water ) : - 285.8 kj/mole

h2o ( water vapor ) : - 241.8 kj / mole.

δhrxn = - 241. 8 - ( - 285.8 )= -241.8 + 285.8 = 44.0

answer: 44.0 kj"

pie chart because it is in percents ( % )