How many liters of a 0.45% half-normal saline (m/v) solution for iv therapy can be prepared from 33 grams of sodium chloride?

The concentration 0.45% means that there is 0.45% weight of normal saline(sodium chloride) in the solution. In this question, there is 33 gram of sodium chloride in the solution. Assuming the solvent is water which has 1000gr/liter density, then the solution volume should be:

NaCl weight= 0.45% * water mass
NaCl weight= 0.45% * water density* water volume
33g= 0.45%* 1000g/l * water volume
water volume= 33g/ (0.45% * 1000g/l)
water volume= 7.33 liter

Ido not understand.