The specific heat of silver (ag) is 0.245 j/ºc g. determine the energy required to raise the temperature of 350 g of ag from 293 k to 400 k.

9180 Joules First determine how many degrees the temperature is being changed. 400 K - 293 K = 107 K Since the units K and C have the same magnitude (they just have a different 0 point). We can freely exchange them when merely speaking of differences and not absolute values. So we can express the specific heat of silver as 0.245 J/ÂşC g or 0.245 J/K g. In any case, we now have 3 values with the units J/K g, g, and K. We desire a result with the units J. So it's a simple matter of multiplication and division such that we get the desired unit. Let's start with our specific heat 0.245 J/(K g) And let's cancel out the g term. Multiplying by our g term will do nicely. So 0.245 J/(K g) * 350 g = 85.75 J/K Now let's cancel out the K term. Another multiplication will do it. 85.75 J/K * 107 K = 9175.25 J Since we only have 3 significant figures in our data, round to 3 significant figures, giving 9180 J.

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