If you wish to warm 52 kg of water by 22 ∘c for your bath, find what the quantity of heat is needed. express your answer in calories cal.

Given:
 m = 52 kg. the mass of water 
ΔT = 22 °C, the temperature increase

Note that
c = 4.184 J/(g-°C), the specific heat of water.

The quantity of heat required is
Q = mcΔT
    = (52,000 g)*(4.184 J/(g-°C))*(22 °C)
    = 4.7865 x 10⁴ J

Because 1 J = 2.39 x 10⁻⁴ cal. the heat required is
Q = (4.7865 x 10⁴ J)*(2.39 x 10⁻⁴ cal/J) = 1143.97 cal ≈ 1144 cal

1144 cal

What are the choices?