The ka of acetic acid ch3co2h is 1.8 x10-5. what is the ph

You must know the concentration of the acetic acid. Suppose the concentration is 0.1 M. The solution is as follows:

            CH₃COOH → CH₃COO⁻ + H⁺
 I                  0.1               0              0
C                 -x                +x            +x
E              0.1 - x             x               x

Ka = (x)(x)/(0.1 - x)
1.8×10⁻⁵ = x²/(0.1 - x)
Solving for x,
x = 1.333×10⁻³ = H⁺

pH = -log[H⁺] = -log(1.333×10⁻³)
pH = 2.88

The answer is b i think

I’d have to say no because without oxygen in the water the fish would all be dead. so if you want to fish for dead fish, pick the ponds with the lowest oxygen concentrations.