C3h2n, 208.19 g/mol chemical formula?

First, determine the molar mass of the empirical formula given for the substance. This can be solved by adding the products of the number of moles and the molar mass of each of the atom as shown below,
 
         M = (3 mols C)(12 g C/1 mol C) + (2 mols H)(1 g H/1 mol H) + (1 mol N)(14 g N/1 mol N)
         M = 52 g/mol

Then, divide the given molar mass above by the calculated value.
       n = 208.19 g/mol / 52 g/mol = 4 

Then, multiply the value of n to the coefficients of the atoms giving us the answer.

 ANSWER: C₁₂H₈N₄

There is no reason to think the results are biased or not conducted properly but you should not assume the results are correct just because they were done in a laboratory so the answer would be c. it is likely to be reliable because the results support the conclusion presented.