What is the mass of a 1.69-l sample of a liquid that has a density of 0.921g/ml?

The mass is 1610 g.

D=MV, where D is density, M is mass, V is volume

Known/Given
D=0.921 g/mL
V=1.75 L×1000mL1L=1750 mL

Unknown
M

Equation
D=MV

Solution
Rearrange the equation to isolate the mass and solve for mass.

M=D×V=0.921g/mL×1750mL=1611.75 g=1610 g with three significant figures.

The following diagram helps to understand how to manipulate the density equation so solve for any of the variables.

The following Density Triangle will help you determine how to solve for any missing variable. Put your finger over the missing variable to see what you need to do to solve for it. For example, if you need to find volume, put your finger over the V, and you get M÷D.

https://www.teacherspayteachers.com/Product/Science-Journal-Density-Triangle-Foldable-Completed-4360...

1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%

a rain shadow is a dry region of land on the side that is protected against the prevailing winds of a mountain range. the prevailing winds are the winds that occur most of the time in a particular place of the earth

prevailing winds carry air toward the mountain range. as the air rises up over a mountain range, the air cools, water vapor condenses, and clouds form. on this side of the mountains, called the windward side, precipitation falls in the form of  rain  or snow. this dry air produces a  rain shadow.