Chemistry, 05.07.2019 00:40 sam10146

The reaction below has an equilibrium constant kp=2.2×106 at 298 k. 2cof2(g)⇌co2(g)+cf4(g) calculate kp for the reaction below. cof2(g)⇌12co2(g)+12cf4(g)

Answers: 1

Show answers

Answers

Answer from: janshnajdajdnnahjd

I believe the correct 2nd reaction is:

cof2(g)⇌1/2 co2(g)+1/2 cf4(g)

where we can see that it is exactly one-half of the original

Therefore the new Kp is:

new Kp = (old Kp)^(1/2)

new Kp = (2.2 x 10^6)^(1/2)

new Kp = 1,483.24

Answer from: frisha

Kp = 1.483 . 10³Further explanation

The equilibrium constant is the ratio of concentration or pressure between the results of the reaction / product and the reactant with each reaction coefficient raised

The equilibrium constant is based on the concentration (Kc) in a reaction

pA + qB -----> mC + nD

$\large {\boxed {\bold {Kc ~ = ~ \frac {[C] ^ m [D] ^ n} {[A] ^ p [B] ^ q}}}}$

While the equilibrium constant is based on partial pressure

$\large {\boxed {\bold {Kp ~ = ~ \frac {[pC] ^ m [pD] ^ n} {[pA] ^ p [pB] ^ q}}}}$

The value of Kp and Kc can be linked to the formula '

$\large {\boxed {\bold {Kp ~ = ~ Kc. (R.T) ^ {\Delta n}}}}$

R = gas constant = 0.0821 L.atm / mol.K

=n = number of product coefficients-number of reactant coefficients

There are rules in determining the Kp value for the related reaction

1. If the reaction equation is reversed, the value of Kp is also reversed 2. if the reaction coefficient is divided by a factor n, then the new Kp value is the square root of n from the old Kp 3. if the reaction coefficient is multiplied by the factor n, then the new Kp value is the power of n from the old Kp

2COF₂ (g) ⇌CO₂(g) + CF₄ (g) Kp = 2.2 × 10⁶ at 298 K(reaction 1)

$\rm COF_2(g)---\dfrac{1}{2}CO_2(g)+\dfrac{1}{2}CF_4(g) (reaction\:2)$

For the reaction 2, the reaction coefficient is divided by 2, so the new Kp value :

$\rm Kp=\sqrt{2.2.10^6}\\\\Kp=1.483.10^3$

Learn more

an equilibrium constant link

link

Calculate the value of the equilibrium constant, Kc

link

Concentration of hi at equilibrium

link

Answer from: Quest

why do the isotopes of a particular element behave differently in nuclear reactions but the same in chemical reactions? chemical reactions involve changes to electrons in an atom; isotopes do not differ in electrons, and so they react the same way during chemical changes.

Answer from: Quest

ill try to . no promises tho.

explanation:

Another question on Chemistry

Chemistry, 22.06.2019 00:10

According to the diagram; a) identify the anode of the cell and write the half-reaction that occurs there b) write the overall equation for the reaction that occurs as the cell operates c) calculate the value of the standard cell potential ,e cell. d)write the shorthand notation of the cell above e)indicate the flow of the electrons on the diagram

Answers: 3

Answer

Chemistry, 22.06.2019 15:30

What is the atomic number of an atom that has 6 protons

Answers: 1

Answer

Chemistry, 22.06.2019 19:50

If a gas has an initial pressure of 101kpa and a volume of 10l, then it expands to a volume of 20l, what is the new pressure?

Answers: 2

Answer

Chemistry, 23.06.2019 06:00

•what conclusions can you make about the relationship between the volume of a gas and its temperature? • what conclusions can you make about the relationship between the volume of a gas and its pressure? • what possible variables have you not accounted for? as you did the procedures, is it possible that the atmospheric pressure may have changed? if it did change over the course of your experiment, then how would your results have been affected?

Answers: 3

Answer

You know the right answer?

The reaction below has an equilibrium constant kp=2.2×106 at 298 k. 2cof2(g)⇌co2(g)+cf4(g) calculate...

Questions