Calculate the specific heat of a substance when 63j of energy are transferred as heat to an 8.0 g sample to raise it temperature from 314 k to 340 k

Answer : The specific heat of substance is 0.30 J/g.K

Explanation :

Formula used :

or,

where,

Q = heat = 63 J

m = mass of substance = 8.0 g

= specific heat of substance = ?

= initial temperature  = 314 K

= final temperature  = 340 K

Now put all the given value in the above formula, we get:

Therefore, the specific heat of substance is 0.30 J/g.K

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