A74.28-g sample of ba(oh)2 is dissolved in enough water to make 2.450 liters of solution. how many ml of this solution must be diluted with water in order to make 1.000 l of 0.100 m ba(oh)2?

First let us calculate the initial molarity of the 2.45 L of solution. Molar mass = 171.34 g/mol

moles Ba(OH)2 = 74.28 g * (1 mole / 171.34 g) =  0.4335 moles

Molarity (M1) = 0.4335 moles / 2.45 L = 0.177 M

Now using the formula M1V1 = M2V2, we can calculate how much to dilute (V1):

0.177 * V1 = 0.1 * 1

V1 = 0.56 L

Therefore 0.56 L of the initial solution must be diluted to 1 L to make 0.1 M

the answer is b because, investigating whether another species of moth also drinks tears might be interesting, but it would not directly explain why this species of moth does.

to explain why this species of moth drinks tears, the scientist could ask: "what nutrients that moths need are in elephant tears? "

the scientist could experiment with moth repellent or oter ways to keep the moths away, but that would not answer his original question.