Agas mixture contains rn, he and n2. what is the total pressure of the mixture, if the mole fraction of n2 is 0.350 and the pressure of n2 is 0.580 atm?

We can solve this problem using Raoults law. The formula for Raoults law is:

P_a = X_a * P

where,

P_a = the partial pressure of substance A

X_a = the mole fraction of substance A

P = total pressure

Therefore calculating for P:

P = P_a / X_a

P = 0.580 atm / 0.35

P = 1.657 atm

number of molecules / avogadro's number * molecule molecular = mass

explanation:

we define a gram-molecular weight as the mass of one mole of any element or compound. a mole contains avogadro's number of units (molecules) –  

6.022

x

10

23

. so, dividing the number of molecules by avogadro's number gives us the number of moles. multiplying that by the molecular weight gives us the mass. from the periodic table we find the gram-molecular weight of u to be238 and of f to be19. so,  

u

f

6

will have a gram-molecular weight of 352g.

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