If you produce 14.5 g of o2 in the lab from a reaction that you showed by calculation could produce a maximum of 22.0 g of o2, what is your percent yield?

65.9 %

Explanation:

The formula for calculating percentage yield is:

Percentage yield =

Given : Experimental yield = 14.5 g

Theoretical yield = 22.0 g

Putting in the values we get:

Percentage yield =

Therefore, the percentage yield is 65.9 %.

it would be a gas formation

c is having 4 valence electrons and is bonded to three hydrogens and one sulphur atom, therefore, the number of bond pair is equal to four. as all the valence electrons are used in forming the bonds so, there is no lone pair left on carbon.

s is having 6 valence electrons and is bonded to one other sulfur atom and one carbon atom, therefore, the number of bond pair is equal to 2. as only two valence electrons are used in forming the bonds so, four electrons are left. therefore, two lone pairs are present on s.