Compound a has a pka of 7 and compound b has a pka of 10. compound a is how many times more acidic than compound b?

Compound A is 1000 times more acidic than compound B

The pKa value is an indicator of the strength of an acid

The pKa is a logarithmic function. pKa is the negative logarithm to the base ten of Ka

pKa = - log Ka

The smaller the pKa, the stronger the acid

A difference of 1 pKa shows a difference of 10 times in the acidity

Suppose there is a difference of 3 pKa units, then corresponds to a 10³ difference in acidity

Compound A has a pKa of 7 and compound B has a pKa of 10.

Because the value of pKa compound A is smaller than compound B, compound A is more acidic than compound B

Ka value of each compound:

pKa = 7

pKa = - log Ka

7 = - log Ka

Ka = 10⁻⁷

pKa = 10

pKa = - log Ka

10 = - log Ka

Ka = 10⁻¹⁰

So that the difference in acidity

10⁻⁷ / 10¹⁰ = 10³ = 1000 times

The pH scale is a measurement system

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the ka reaction of hcn

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strong enough acids to react almost completely with a hydroxide ion

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Keywords: pKa, strong acid, logarithmic function, compound

you did not give any options thus this is the best answer i can give to you with this little information you have given

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