Classify each reaction as synthesis, decomposition, single-displacement, or double-displacement. (a). H2 + O2 —> H2O
(b). N2H4(l) —> NH3(g)+N2(g)
(c). H2SO4+NAOH—> H2O+Na2SO4
(d). Al2(CO3)3 -^-> Al2O3+CO2
(e). NH4I+Cl2–> NH4Cl+I2

i think its 5049.

i hope this !

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2

the answer is c i took the test

the objects have the same charge is correct.

nathan lee