1. Combine equations 1,2,3 to obtain equation 4. Then provide an equation for calculating the heat of reaction in kJ/mol. Equation 1: MgO(s)+2HCl(aq)--->MgCl2(aq)+H2O (l)

Equation 2: Mg(s)+2HCl(aq)>MgCl2(aq)+H2(g)
Equation 3: H2(g)+1/2O2(g)>H2O(l)

Magnesium is the limiting reactant in this experiment. calculate the theoretical yield of mgo for each trial. trial 1: trial 2: data mass of empty crucible with lid trial 1: 26.688 trial 2: 26.681 mass of mg metal, crucible, and lid trial 1: 26.994 trial: 2 26.985 mass of mgo, crucible, and lid trial 1: 27.188 trial 2: 27.180