Find the empirical formula of the compound which contains 67.6% Hg, 10.8% S, and 21.6% O.

Explanation:

Divide 67.6% by 201 of mercury

Divide 10.8% by 32 of sulfur

Divide 21.6% by 16 of oxygen

Then divide number by itself .

Example : Divide 2.97 by both sulfer moles and oxygen moles . Multiply by 2 to get whole number

it’s previous models   because when i picked that son of a gun’s answer it was wrong look for previous models because they might make it a different letter  

c) should be the answer.