If 18.75 mole of helium gas is at 10oC and gauge pressure of 0.350 atm. (a) Calculate the volume of the helium gas under these condition and (b) calculate the temperature if the gas is compressed to precisely half the volume at a gauge pressure of 1.00 atm.

number of molecules / avogadro's number * molecule molecular = mass

explanation:

we define a gram-molecular weight as the mass of one mole of any element or compound. a mole contains avogadro's number of units (molecules) –  

6.022

x

10

23

. so, dividing the number of molecules by avogadro's number gives us the number of moles. multiplying that by the molecular weight gives us the mass. from the periodic table we find the gram-molecular weight of u to be238 and of f to be19. so,  

u

f

6

will have a gram-molecular weight of 352g.

so what is the problem with your lab report and whats the subject of the lab report? i will you

the electron configuration that you gave me has 16 electrons ergo it has 16 protons ergo it is the element sulfur.