Throughout the reflection, make sure you have a copy of the Student Guide and your data tables. Use the drop-down menus to complete the statements. In Part I of this experiment, the
was intentionally manipulated. This was the independent variable. The dependent variable measured was the
.

In Part II of this experiment, the
was intentionally manipulated. This was the independent variable. The dependent variable measured was the
.

this is out of context was there an image with the question so we can help more???

1. mas and type of material

2. type of material

3. temperature

Explanation:

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as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2