If it takes 30.3ml of 2.5m naoh to neutralize 20ml of h2so4 in a battery. what is the molarity of h2so4

              1.89 M

Explanation:

First calculate moles of NaOH

M = moles/Vol in L

moles = M x Vol in L

moles = 2.5 M x 0.0303 L

moles = 0.07575 moles

Also, the reaction between NaOH and H2SO4 is

2 NaOH + H2SO4 >  Na2SO4 + 2 H2O

For every one mole of H2SO4, 2 moles of NaOH reacts.

So, for 0.07575 moles of NaOH, 0.037875 moles of H2SO4 will react.

Now, calculate molarity of H2SO4

M = moles / Vol in L

M = 0.037875 mol / 0.02 L

M = 1.89 M

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