Tetracaine can be synthesized from benzene. The synthesis involves the following steps: Benzene CH3Cl, AlCl3 to form product A; A HNO3, H2SO4 to form product B; B KMnO4, H2O to form product C; C SOCl2 to form product D; D HOCH2CH2N(CH3)2 to form product E; E H2, Pt to form product F; F CH3CH2CH2CHO to form product G; G NaBH3CN to form Tetracaine. Draw the structures of product A and product G. You do not have to consider stereochemistry. You do not have to explicitly draw H atoms. Do not include lone pairs in your answer. They will not be considered in the grading. Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right corner. Show the order of synthesis by drawing a reaction arrow between A and G, pointing toward the later-synthesized product.

first, consult an activity series chart to determine if al is more reactive than fe. it is, so it will replace the fe. now, one can continue with the problem.

next, make sure you have a correctly balanced equation.

3feo + 2al ==> 3fe + al2o3

now, determine which reactant (feo or al) is in limiting supply.

moles feo present = 125 g x 1 mole/71.8 g = 1.74 moles

moles al present = 25.0 g x 1 mole/26.98 g = 0.927 moles

since from the balanced equation, it take 3 mol feo for every 2 mol al, al will be limiting.

you can determine this simply by dividing moles of each by their coefficient in the balanced equation. for example: 1.74/3 = 0.58 and 0.927/2 = 0.464. al is less, so it is limiting.

finally, using the stoichiometry in the balanced eq. determine mass of fe that can be produced from 0.927 moles of al.

0.927 moles al x 3 moles fe/2 moles al x 55.8 g/mole = 77.6 g