How many atoms are in 80.45 g of magnesium with explanation

There are 1.9926 * 10 ^24 atoms.

Explanation:

M ( Mg ) = 80.45 g

We can find the molar mass of magnesium in the Periodic table:

M ( Mg ) = 24.31 g / mole

n = 80.45 g : 24.31 g/mole = 3.31 moles

N a ( Avogadro`s constant ) = 6.02 * 10 ^23

N = Na * n = 6.02 * 10 ^24 * 3.31 = 19.926 * 10 ^23

it's c. elements are placed in rows based on how may valencies electrons have.

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